What are the solutions to the equation 16-5(x+7)^2=0 ?

The solutions to the equation 16-5(x+7)^2=0 are x= 4/(sqrt(5))-7,x=-4/(sqrt(5))-7

Find the zeros of 16-5(x+7)^2=0

The zeros of 16-5(x+7)^2=0 are x= 4/(sqrt(5))-7,x=-4/(sqrt(5))-7

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16 - 5 (x + 7)^{2} = 0

x = \frac{4}{5} - 7, x = - \frac{4}{5} - 7

Solution steps

16 - 5 (x + 7)^{2} = 0

Move

16

to the right side

- 5 (x + 7)^{2} = - 16

Divide both sides by

- 5

(x + 7)^{2} = \frac{16}{5}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = \frac{16}{5} : x = \frac{4}{5} - 7

Solve

x + 7 = - \frac{16}{5} : x = - \frac{4}{5} - 7

The solutions to the quadratic equation are:

x = \frac{4}{5} - 7, x = - \frac{4}{5} - 7

\frac{11 !}{( 11 - 11 ) !}

5 x - 18 = 3 x + 42

2 x + 3 = x + x + 3

7 x + 13 = 34

9 x^{2} - 36 x y + 11 y^{2}

What are the solutions to the equation 16-5(x+7)^2=0 ?
The solutions to the equation 16-5(x+7)^2=0 are x= 4/(sqrt(5))-7,x=-4/(sqrt(5))-7
Find the zeros of 16-5(x+7)^2=0
The zeros of 16-5(x+7)^2=0 are x= 4/(sqrt(5))-7,x=-4/(sqrt(5))-7