What are the solutions to the equation x^2+34x-72=0 ?

The solutions to the equation x^2+34x-72=0 are x=2,x=-36

Find the zeros of x^2+34x-72=0

The zeros of x^2+34x-72=0 are x=2,x=-36

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x^{2} + 34 x - 72 = 0

x = 2, x = - 36

Solution steps

x^{2} + 34 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 34 \pm 3 4 ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

3 4^{2} - 4 \cdot 1 \cdot (- 72) = 38

x_{1, 2} = \frac{- 34 \pm 38}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 34 + 38}{2 \cdot 1}, x_{2} = \frac{- 34 - 38}{2 \cdot 1}

x = \frac{- 34 + 38}{2 \cdot 1} : 2

x = \frac{- 34 - 38}{2 \cdot 1} : - 36

The solutions to the quadratic equation are:

x = 2, x = - 36

9^{1.5}

2 x - 3 = x + 2

\frac{c ^{9} d ^{- 7}}{c ^{14} d ^{- 10}}

x^{2} - 3 x + 1 \leq 0

2 lo g_{7} (- 2 r)

What are the solutions to the equation x^2+34x-72=0 ?
The solutions to the equation x^2+34x-72=0 are x=2,x=-36
Find the zeros of x^2+34x-72=0
The zeros of x^2+34x-72=0 are x=2,x=-36