What is factor z^2+2z+1-w^2 ?

The solution to factor z^2+2z+1-w^2 is (z+1+w)(z+1-w)

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factor z^2+2z+1-w^2

factor

z^{2} + 2 z + 1 - w^{2}

(z + 1 + w) (z + 1 - w)

Solution steps

z^{2} + 2 z + 1 - w^{2}

Factor

z^{2} + 2 z + 1 : (z + 1)^{2}

= (z + 1)^{2} - w^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(z + 1)^{2} - w^{2} = ((z + 1) + w) ((z + 1) - w)

= ((z + 1) + w) ((z + 1) - w)

Apply rule:

(a) = a

(z + 1) = z + 1

= (z + 1 + w) (z + 1 - w)

\frac{5 n ^{2} - 245}{7 n ^{2} + 112 n + 441}

\frac{3}{4} - \frac{7}{8}

4 x^{2} + 20 = 0

lo g_{12} (1)

- (190 \cdot 1 \cdot (- 35)) = 104 \cdot 15 \cdot 0.5 + 104 \cdot 80

What is factor z^2+2z+1-w^2 ?
The solution to factor z^2+2z+1-w^2 is (z+1+w)(z+1-w)