What is the answer to |0.2x+5|=x^2-2 ?

The answer to |0.2x+5|=x^2-2 is x=(1-sqrt(701))/(10)\lor x=(1+sqrt(701))/(10)

Solve for x: |0.2x+5|=x^2-2

The solution is x=(1-sqrt(701))/(10)\lor x=(1+sqrt(701))/(10)

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∣ 0.2 x + 5 ∣ = x^{2} - 2

x = \frac{1 - 701}{10} or x = \frac{1 + 701}{10}

Decimal Notation

x = - 2.54764 \dots, x = 2.74764 \dots

Solution steps

∣ 0.2 x + 5 ∣ = x^{2} - 2

Find positive and negative intervals

x < - 25, x \geq - 25

Solve the inequality for each interval

No Solution or (x = \frac{1 - 701}{10} or x = \frac{1 + 701}{10})

x = \frac{1 - 701}{10} or x = \frac{1 + 701}{10}

3 ∣ 3 (x + 5) (x - 1) ∣ + 5 = 32

- 5 ∣ 6 - h ∣ + 7 = - 13

- ∣ - x ∣ = - 9

3 ∣ 8 x - 6 ∣ = 3

2 ∣ x - 25 ∣ + 4 = 12

What is the answer to |0.2x+5|=x^2-2 ?
The answer to |0.2x+5|=x^2-2 is x=(1-sqrt(701))/(10)\lor x=(1+sqrt(701))/(10)
Solve for x: |0.2x+5|=x^2-2
The solution is x=(1-sqrt(701))/(10)\lor x=(1+sqrt(701))/(10)