What are the solutions to the equation a^2-10a=-24 ?

The solutions to the equation a^2-10a=-24 are a=6,a=4

Find the zeros of a^2-10a=-24

The zeros of a^2-10a=-24 are a=6,a=4

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a^{2} - 10 a = - 24

a = 6, a = 4

Solution steps

a^{2} - 10 a = - 24

Move

24

to the left side

a^{2} - 10 a + 24 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

a_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, a_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

a = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

a = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

a = 6, a = 4

x^{2} + 9 x - 52 = 0

∣ 2 a + 7 ∣ = ∣ 3 a - 7 ∣

x^{2} \geq 5 x - 6

\frac{1}{2} \leq \frac{1 - 2 t}{3} < \frac{2}{3}

(4 y^{\frac{5}{4}})^{\frac{1}{2}}

What are the solutions to the equation a^2-10a=-24 ?
The solutions to the equation a^2-10a=-24 are a=6,a=4
Find the zeros of a^2-10a=-24
The zeros of a^2-10a=-24 are a=6,a=4