What is the answer to |x^4-2x^2-2|=0 ?

The answer to |x^4-2x^2-2|=0 is x=-sqrt(1+\sqrt{3)}\lor x=sqrt(1+\sqrt{3)}

Solve for x: |x^4-2x^2-2|=0

The solution is x=-sqrt(1+\sqrt{3)}\lor x=sqrt(1+\sqrt{3)}

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x^{4} - 2 x^{2} - 2 = 0

x = - 1 + 3 or x = 1 + 3

Decimal Notation

x = - 1.65289 \dots, x = 1.65289 \dots

Solution steps

x^{4} - 2 x^{2} - 2 = 0

Apply absolute rule: If

∣ u ∣ = 0

then

u = 0

x^{4} - 2 x^{2} - 2 = 0

x^{4} - 2 x^{2} - 2 = 0 : x = 1 + 3, x = - 1 + 3

x = - 1 + 3 or x = 1 + 3

∣ q + 4 ∣ = 4

∣ 4 n - 2 ∣ = 2

2 - 3 x = - 10 + 3 ∣ 2 - 2 x ∣

∣ 2 x - 10 ∣ = 10

(x + 1) = ∣ x - 5 ∣

What is the answer to |x^4-2x^2-2|=0 ?
The answer to |x^4-2x^2-2|=0 is x=-sqrt(1+\sqrt{3)}\lor x=sqrt(1+\sqrt{3)}
Solve for x: |x^4-2x^2-2|=0
The solution is x=-sqrt(1+\sqrt{3)}\lor x=sqrt(1+\sqrt{3)}