What is the answer to |x^2-7x+4|=0 ?

The answer to |x^2-7x+4|=0 is x=(7-sqrt(33))/2 \lor x=(7+sqrt(33))/2

Solve for x: |x^2-7x+4|=0

The solution is x=(7-sqrt(33))/2 \lor x=(7+sqrt(33))/2

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x^{2} - 7 x + 4 = 0

x = \frac{7 - 33}{2} or x = \frac{7 + 33}{2}

Decimal Notation

x = 0.62771 \dots, x = 6.37228 \dots

Solution steps

x^{2} - 7 x + 4 = 0

Apply absolute rule: If

∣ u ∣ = 0

then

u = 0

x^{2} - 7 x + 4 = 0

x^{2} - 7 x + 4 = 0 : x = \frac{7 + 33}{2}, x = \frac{7 - 33}{2}

x = \frac{7 - 33}{2} or x = \frac{7 + 33}{2}

∣ b + 3 ∣ - 3 = 5

9 ∣ 29 - 8 x ∣ = 2 x + 3

∣ P + 35 ∣ = 10

∣ 2 x - 1 ∣ = 6 x - 3

∣ - 8 + x ∣ = 2

What is the answer to |x^2-7x+4|=0 ?
The answer to |x^2-7x+4|=0 is x=(7-sqrt(33))/2 \lor x=(7+sqrt(33))/2
Solve for x: |x^2-7x+4|=0
The solution is x=(7-sqrt(33))/2 \lor x=(7+sqrt(33))/2