What is 9-sqrt(x+4)<= 6 ?

The solution to 9-sqrt(x+4) = 5

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9-sqrt(x+4)<= 6

9 - x + 4 \leq 6

x \geq 5

Interval Notation

[5, \infty)

Solution steps

9 - x + 4 \leq 6

Move

9

to the right side

- x + 4 \leq - 3

Multiply both sides by

- 1

x + 4 \geq 3

Square both sides

(x + 4)^{2} \geq 3^{2}

Simplify

x + 4 \geq 9

Move

4

to the right side

x \geq 5

Find singularity points

Find non-negative values for radicals:

x \geq - 4

Combine the intervals

x \geq 5 and x \geq - 4

Merge Overlapping Intervals

x \geq 5

x^{3} - 6 x - 4

- 40 + 28 x^{3}

- 1.7 x = 17

∣ x - 2 ∣ \geq 0

10 a + 20