What are the solutions to the equation x^2+0.2*(1-x)=0 ?

The solutions to the equation x^2+0.2*(1-x)=0 are x= 1/10+i(sqrt(19))/(10),x= 1/10-i(sqrt(19))/(10)

Find the zeros of x^2+0.2*(1-x)=0

The zeros of x^2+0.2*(1-x)=0 are x= 1/10+i(sqrt(19))/(10),x= 1/10-i(sqrt(19))/(10)

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x^{2} + 0.2 \cdot (1 - x) = 0

x = \frac{1}{10} + i \frac{19}{10}, x = \frac{1}{10} - i \frac{19}{10}

Solution steps

x^{2} + 0.2 (1 - x) = 0

Multiply both sides by

10

10 x^{2} + 2 (1 - x) = 0

Expand

10 x^{2} + 2 (1 - x) : 10 x^{2} + 2 - 2 x

10 x^{2} + 2 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

10 x^{2} - 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 10 \cdot 2}{2 \cdot 10}

Simplify

(- 2)^{2} - 4 \cdot 10 \cdot 2 : 219 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 19 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 19 i}{2 \cdot 10}, x_{2} = \frac{- ( - 2 ) - 2 19 i}{2 \cdot 10}

x = \frac{- ( - 2 ) + 2 19 i}{2 \cdot 10} : \frac{1}{10} + i \frac{19}{10}

x = \frac{- ( - 2 ) - 2 19 i}{2 \cdot 10} : \frac{1}{10} - i \frac{19}{10}

The solutions to the quadratic equation are:

x = \frac{1}{10} + i \frac{19}{10}, x = \frac{1}{10} - i \frac{19}{10}

\frac{3}{8 x ^{3} y ^{3}} - \frac{1}{4 x y}

300 x > 160.5 x + 69750

\frac{7 ^{7}}{7 ^{5}}

(2 x - \frac{3}{4}) (x - \frac{1}{2}) = 31

\frac{142.17 ( 1.2 )}{( 32.11 ) ( 79.1 )}

What are the solutions to the equation x^2+0.2*(1-x)=0 ?
The solutions to the equation x^2+0.2*(1-x)=0 are x= 1/10+i(sqrt(19))/(10),x= 1/10-i(sqrt(19))/(10)
Find the zeros of x^2+0.2*(1-x)=0
The zeros of x^2+0.2*(1-x)=0 are x= 1/10+i(sqrt(19))/(10),x= 1/10-i(sqrt(19))/(10)