What is the answer to |x^2+4x|=5x+12 ?

The answer to |x^2+4x|=5x+12 is x=-(9-sqrt(33))/2 \lor x=4

Solve for x: |x^2+4x|=5x+12

The solution is x=-(9-sqrt(33))/2 \lor x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 4 x = 5 x + 12

x = - \frac{9 - 33}{2} or x = 4

Decimal Notation

x = - 1.62771 \dots, x = 4

Solution steps

x^{2} + 4 x = 5 x + 12

Find positive and negative intervals

x \leq - 4, - 4 < x < 0, x \geq 0

Solve the inequality for each interval

No Solution or x = - \frac{9 - 33}{2} or x = 4

x = - \frac{9 - 33}{2} or x = 4

∣ 10 x + 9 ∣ = 5

6 = ∣ - 2 j ∣ + 2

∣ z - 9 ∣ = 1

2 ∣ x + 4 ∣ + 4 = 2

6 + 4 ∣ 8 x - 2 ∣ = 30

What is the answer to |x^2+4x|=5x+12 ?
The answer to |x^2+4x|=5x+12 is x=-(9-sqrt(33))/2 \lor x=4
Solve for x: |x^2+4x|=5x+12
The solution is x=-(9-sqrt(33))/2 \lor x=4