What are the solutions to the equation x^2+2x+16=0 ?

The solutions to the equation x^2+2x+16=0 are x=-1+sqrt(15)i,x=-1-sqrt(15)i

Find the zeros of x^2+2x+16=0

The zeros of x^2+2x+16=0 are x=-1+sqrt(15)i,x=-1-sqrt(15)i

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x^{2} + 2 x + 16 = 0

x = - 1 + 15 i, x = - 1 - 15 i

Solution steps

x^{2} + 2 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 16 : 215 i

x_{1, 2} = \frac{- 2 \pm 2 15 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 15 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 15 i}{2 \cdot 1}

x = \frac{- 2 + 2 15 i}{2 \cdot 1} : - 1 + 15 i

x = \frac{- 2 - 2 15 i}{2 \cdot 1} : - 1 - 15 i

The solutions to the quadratic equation are:

x = - 1 + 15 i, x = - 1 - 15 i

\frac{3}{4} - \frac{5}{8} + \frac{7}{12}

\frac{5 x - 4}{2 x + 1} > 1

n^{2} - 19 n + 90

\frac{2}{n} - \frac{1}{n + 1}

448

What are the solutions to the equation x^2+2x+16=0 ?
The solutions to the equation x^2+2x+16=0 are x=-1+sqrt(15)i,x=-1-sqrt(15)i
Find the zeros of x^2+2x+16=0
The zeros of x^2+2x+16=0 are x=-1+sqrt(15)i,x=-1-sqrt(15)i