What is the answer to |2x^3+8|-7=11 ?

The answer to |2x^3+8|-7=11 is x=-\sqrt[3]{13}\lor x=\sqrt[3]{5}

Solve for x: |2x^3+8|-7=11

The solution is x=-\sqrt[3]{13}\lor x=\sqrt[3]{5}

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2 x^{3} + 8 - 7 = 11

Decimal Notation

x = - 2.35133 \dots, x = 1.70997 \dots

Solution steps

2 x^{3} + 8 - 7 = 11

Move

7

to the right side

2 x^{3} + 8 = 18

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

2 x^{3} + 8 = - 18 or 2 x^{3} + 8 = 18

2 x^{3} + 8 = - 18 or 2 x^{3} + 8 = 18

\frac{1}{2} x - 3 = 0

\frac{1}{2} x - 3 = 2

∣ 4 w + 6 ∣ - 39 = - 5

∣ m - 2 ∣ = 0

∣ m - 2 ∣ = 4

What is the answer to |2x^3+8|-7=11 ?
The answer to |2x^3+8|-7=11 is x=-\sqrt[3]{13}\lor x=\sqrt[3]{5}
Solve for x: |2x^3+8|-7=11
The solution is x=-\sqrt[3]{13}\lor x=\sqrt[3]{5}