What is the answer to x^2+8x+1=|x+6|+6 ?

The answer to x^2+8x+1=|x+6|+6 is x=(-9-sqrt(77))/2 \lor x=(-7+sqrt(93))/2

Solve for x: x^2+8x+1=|x+6|+6

The solution is x=(-9-sqrt(77))/2 \lor x=(-7+sqrt(93))/2

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x^{2} + 8 x + 1 = ∣ x + 6 ∣ + 6

x = \frac{- 9 - 77}{2} or x = \frac{- 7 + 93}{2}

Decimal Notation

x = - 8.88748 \dots, x = 1.32182 \dots

Solution steps

x^{2} + 8 x + 1 = ∣ x + 6 ∣ + 6

Find positive and negative intervals

x < - 6, x \geq - 6

Solve the inequality for each interval

x = \frac{- 9 - 77}{2} or x = \frac{- 7 + 93}{2}

∣ x + 4 ∣ = - 1

∣ x - 2 ∣ + 3 = 15

2 ∣ v + 1 ∣ + 6 = 14

y, ∣ y + 5 ∣ = 1

4 ∣ 5 x ∣ + 5 = 17

What is the answer to x^2+8x+1=|x+6|+6 ?
The answer to x^2+8x+1=|x+6|+6 is x=(-9-sqrt(77))/2 \lor x=(-7+sqrt(93))/2
Solve for x: x^2+8x+1=|x+6|+6
The solution is x=(-9-sqrt(77))/2 \lor x=(-7+sqrt(93))/2