What are the solutions to the equation x^2+7x+26=-5x+6 ?

The solutions to the equation x^2+7x+26=-5x+6 are x=-2,x=-10

Find the zeros of x^2+7x+26=-5x+6

The zeros of x^2+7x+26=-5x+6 are x=-2,x=-10

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x^{2} + 7 x + 26 = - 5 x + 6

x = - 2, x = - 10

Solution steps

x^{2} + 7 x + 26 = - 5 x + 6

Move

6

to the left side

x^{2} + 7 x + 20 = - 5 x

Move

5 x

to the left side

x^{2} + 12 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 20 = 8

x_{1, 2} = \frac{- 12 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 8}{2 \cdot 1}, x_{2} = \frac{- 12 - 8}{2 \cdot 1}

x = \frac{- 12 + 8}{2 \cdot 1} : - 2

x = \frac{- 12 - 8}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 2, x = - 10

- \frac{1}{2} x^{2} + 40 = 0

x^{3} - 7 x^{2} - 8 x

6 (x - 5) = 54

- 4 (5 x - 7) < - 24 x + 8

\frac{8 ^{7}}{8 ^{5}}

What are the solutions to the equation x^2+7x+26=-5x+6 ?
The solutions to the equation x^2+7x+26=-5x+6 are x=-2,x=-10
Find the zeros of x^2+7x+26=-5x+6
The zeros of x^2+7x+26=-5x+6 are x=-2,x=-10