What are the solutions to the equation a^2+6a+9=0 ?

The solutions to the equation a^2+6a+9=0 are a=-3

Find the zeros of a^2+6a+9=0

The zeros of a^2+6a+9=0 are a=-3

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a^{2} + 6 a + 9 = 0

a = - 3

Solution steps

a^{2} + 6 a + 9 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

a_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

a = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

a = - 3

The solution to the quadratic equation is:

a = - 3

15 \cdot \frac{1}{2}

lo g_{25} (\frac{1}{5}) = x

2 \cdot \frac{π}{3}

- \frac{12}{6}

2 n^{2} + 13 n + 11

What are the solutions to the equation a^2+6a+9=0 ?
The solutions to the equation a^2+6a+9=0 are a=-3
Find the zeros of a^2+6a+9=0
The zeros of a^2+6a+9=0 are a=-3