What are the solutions to the equation 9x^2-8=6x ?

The solutions to the equation 9x^2-8=6x are x= 4/3 ,x=-2/3

Find the zeros of 9x^2-8=6x

The zeros of 9x^2-8=6x are x= 4/3 ,x=-2/3

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9 x^{2} - 8 = 6 x

x = \frac{4}{3}, x = - \frac{2}{3}

Decimal Notation

x = 1.33333 \dots, x = - 0.66666 \dots

Solution steps

9 x^{2} - 8 = 6 x

Move

6 x

to the left side

9 x^{2} - 8 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} - 6 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 ( - 8 )}{2 \cdot 9}

(- 6)^{2} - 4 \cdot 9 (- 8) = 18

x_{1, 2} = \frac{- ( - 6 ) \pm 18}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 18}{2 \cdot 9}, x_{2} = \frac{- ( - 6 ) - 18}{2 \cdot 9}

x = \frac{- ( - 6 ) + 18}{2 \cdot 9} : \frac{4}{3}

x = \frac{- ( - 6 ) - 18}{2 \cdot 9} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - \frac{2}{3}

\frac{a ^{2} - b ^{2}}{a + b}

3 (x + 5) \leq 0

x^{3} + x^{2} - 10 x + 8 \geq 0

(\frac{20}{29})^{2} - (\frac{21}{29})^{2}

\frac{7}{3} \cdot 2

What are the solutions to the equation 9x^2-8=6x ?
The solutions to the equation 9x^2-8=6x are x= 4/3 ,x=-2/3
Find the zeros of 9x^2-8=6x
The zeros of 9x^2-8=6x are x= 4/3 ,x=-2/3