What is the answer to |x^2-2x-1|=1 ?

The answer to |x^2-2x-1|=1 is x=1-sqrt(3)\lor x=0\lor x=2\lor x=1+sqrt(3)

Solve for x: |x^2-2x-1|=1

The solution is x=1-sqrt(3)\lor x=0\lor x=2\lor x=1+sqrt(3)

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x^{2} - 2 x - 1 = 1

x = 1 - 3 or x = 0 or x = 2 or x = 1 + 3

Decimal

x = - 0.73205 \dots, x = 0, x = 2, x = 2.73205 \dots

Solution steps

x^{2} - 2 x - 1 = 1

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 2 x - 1 = - 1 or x^{2} - 2 x - 1 = 1

x^{2} - 2 x - 1 = - 1 or x^{2} - 2 x - 1 = 1

(x = 0 or x = 2) or (x = 1 - 3 or x = 1 + 3)

x = 1 - 3 or x = 0 or x = 2 or x = 1 + 3

∣ x ∣ = 25.1

4 - 4 ∣ 6 x + 6 ∣ = - 116

∣ y + 4 ∣ - 1 = 4

∣ 2 x + 8 ∣ + 4 = 8

∣ 7 + 3 x ∣ = 11 - x

What is the answer to |x^2-2x-1|=1 ?
The answer to |x^2-2x-1|=1 is x=1-sqrt(3)\lor x=0\lor x=2\lor x=1+sqrt(3)
Solve for x: |x^2-2x-1|=1
The solution is x=1-sqrt(3)\lor x=0\lor x=2\lor x=1+sqrt(3)