What are the solutions to the equation 3x^2+2x=-2 ?

The solutions to the equation 3x^2+2x=-2 are x=-1/3+i(sqrt(5))/3 ,x=-1/3-i(sqrt(5))/3

Find the zeros of 3x^2+2x=-2

The zeros of 3x^2+2x=-2 are x=-1/3+i(sqrt(5))/3 ,x=-1/3-i(sqrt(5))/3

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3 x^{2} + 2 x = - 2

x = - \frac{1}{3} + i \frac{5}{3}, x = - \frac{1}{3} - i \frac{5}{3}

Solution steps

3 x^{2} + 2 x = - 2

Move

2

to the left side

3 x^{2} + 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

Simplify

2^{2} - 4 \cdot 3 \cdot 2 : 25 i

x_{1, 2} = \frac{- 2 \pm 2 5 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 2 5 i}{2 \cdot 3}, x_{2} = \frac{- 2 - 2 5 i}{2 \cdot 3}

x = \frac{- 2 + 2 5 i}{2 \cdot 3} : - \frac{1}{3} + i \frac{5}{3}

x = \frac{- 2 - 2 5 i}{2 \cdot 3} : - \frac{1}{3} - i \frac{5}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{5}{3}, x = - \frac{1}{3} - i \frac{5}{3}

(4 x - 1) (2 x + 3) = 18 x - 4

x^{2} + \frac{8}{3} x + \frac{5}{3} = 0

\frac{( 2 ) ^{2} - 4}{( 2 ) ^{2} + ( 2 ) - 6}

2 (\frac{45}{53}) (\frac{28}{53})

- 9 < \frac{x}{5} - 2

What are the solutions to the equation 3x^2+2x=-2 ?
The solutions to the equation 3x^2+2x=-2 are x=-1/3+i(sqrt(5))/3 ,x=-1/3-i(sqrt(5))/3
Find the zeros of 3x^2+2x=-2
The zeros of 3x^2+2x=-2 are x=-1/3+i(sqrt(5))/3 ,x=-1/3-i(sqrt(5))/3