What is the answer to |x^2+3x-7|=3 ?

The answer to |x^2+3x-7|=3 is x=-5\lor x=-4\lor x=1\lor x=2

Solve for x: |x^2+3x-7|=3

The solution is x=-5\lor x=-4\lor x=1\lor x=2

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x^{2} + 3 x - 7 = 3

x = - 5 or x = - 4 or x = 1 or x = 2

Solution steps

x^{2} + 3 x - 7 = 3

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + 3 x - 7 = - 3 or x^{2} + 3 x - 7 = 3

x^{2} + 3 x - 7 = - 3 or x^{2} + 3 x - 7 = 3

(x = - 4 or x = 1) or (x = - 5 or x = 2)

x = - 5 or x = - 4 or x = 1 or x = 2

x^{2} = 2 x

4 ∣ y - 2 ∣ - 12 = 0

∣ - 4 - 8 m ∣ = 4

∣ x - 6 ∣ + 8 = 13

∣ - 6 f ∣ = 0

What is the answer to |x^2+3x-7|=3 ?
The answer to |x^2+3x-7|=3 is x=-5\lor x=-4\lor x=1\lor x=2
Solve for x: |x^2+3x-7|=3
The solution is x=-5\lor x=-4\lor x=1\lor x=2