What is the answer to |0.127x+9|=x^2 ?

The answer to |0.127x+9|=x^2 is x=(127-sqrt(36016129))/(2000)\lor x=(127+sqrt(36016129))/(2000)

Solve for x: |0.127x+9|=x^2

The solution is x=(127-sqrt(36016129))/(2000)\lor x=(127+sqrt(36016129))/(2000)

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∣ 0.127 x + 9 ∣ = x^{2}

x = \frac{127 - 36016129}{2000} or x = \frac{127 + 36016129}{2000}

Decimal Notation

x = - 2.93717 \dots, x = 3.06417 \dots

Solution steps

∣ 0.127 x + 9 ∣ = x^{2}

Find positive and negative intervals

x < - \frac{9000}{127}, x \geq - \frac{9000}{127}

Solve the inequality for each interval

No Solution or (x = \frac{127 - 36016129}{2000} or x = \frac{127 + 36016129}{2000})

x = \frac{127 - 36016129}{2000} or x = \frac{127 + 36016129}{2000}

11 = ∣ 3 x + 5 ∣

4 ∣ 3 (x + 3) (x - 3) ∣ - 4 = 4

3 ∣ y + 5 ∣ + 7 = 10

3 + 9 ∣ - 5 n ∣ = 48

4 ∣ m ∣ = 0

What is the answer to |0.127x+9|=x^2 ?
The answer to |0.127x+9|=x^2 is x=(127-sqrt(36016129))/(2000)\lor x=(127+sqrt(36016129))/(2000)
Solve for x: |0.127x+9|=x^2
The solution is x=(127-sqrt(36016129))/(2000)\lor x=(127+sqrt(36016129))/(2000)