What are the solutions to the equation y^2+16y=0 ?

The solutions to the equation y^2+16y=0 are y=0,y=-16

Find the zeros of y^2+16y=0

The zeros of y^2+16y=0 are y=0,y=-16

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y^{2} + 16 y = 0

y = 0, y = - 16

Solution steps

y^{2} + 16 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 0 = 16

y_{1, 2} = \frac{- 16 \pm 16}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 16 + 16}{2 \cdot 1}, y_{2} = \frac{- 16 - 16}{2 \cdot 1}

y = \frac{- 16 + 16}{2 \cdot 1} : 0

y = \frac{- 16 - 16}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

y = 0, y = - 16

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- 16 x^{5} y^{4} (x y^{5})

What are the solutions to the equation y^2+16y=0 ?
The solutions to the equation y^2+16y=0 are y=0,y=-16
Find the zeros of y^2+16y=0
The zeros of y^2+16y=0 are y=0,y=-16