What is the answer to |x^2-5x-1|=7 ?

The answer to |x^2-5x-1|=7 is x=(5-sqrt(57))/2 \lor x=2\lor x=3\lor x=(5+sqrt(57))/2

Solve for x: |x^2-5x-1|=7

The solution is x=(5-sqrt(57))/2 \lor x=2\lor x=3\lor x=(5+sqrt(57))/2

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x^{2} - 5 x - 1 = 7

x = \frac{5 - 57}{2} or x = 2 or x = 3 or x = \frac{5 + 57}{2}

Decimal Notation

x = - 1.27491 \dots, x = 2, x = 3, x = 6.27491 \dots

Solution steps

x^{2} - 5 x - 1 = 7

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 5 x - 1 = - 7 or x^{2} - 5 x - 1 = 7

x^{2} - 5 x - 1 = - 7 or x^{2} - 5 x - 1 = 7

(x = 2 or x = 3) or (x = \frac{5 - 57}{2} or x = \frac{5 + 57}{2})

x = \frac{5 - 57}{2} or x = 2 or x = 3 or x = \frac{5 + 57}{2}

5 ∣ b + 7 ∣ = 80

\frac{6 ∣ x - 2 ∣}{4} = 3 x

∣ w ∣ + 13 = 6

3 ∣ 2 x - 5 ∣ = - 9 x

∣ 1.51 x + 3.28 ∣ = 2.15

What is the answer to |x^2-5x-1|=7 ?
The answer to |x^2-5x-1|=7 is x=(5-sqrt(57))/2 \lor x=2\lor x=3\lor x=(5+sqrt(57))/2
Solve for x: |x^2-5x-1|=7
The solution is x=(5-sqrt(57))/2 \lor x=2\lor x=3\lor x=(5+sqrt(57))/2