What is the answer to 9x^2-9|x|-43=0 ?

The answer to 9x^2-9|x|-43=0 is x=-(3+sqrt(181))/6 \lor x=(3+sqrt(181))/6

Solve for x: 9x^2-9|x|-43=0

The solution is x=-(3+sqrt(181))/6 \lor x=(3+sqrt(181))/6

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9 x^{2} - 9 ∣ x ∣ - 43 = 0

x = - \frac{3 + 181}{6} or x = \frac{3 + 181}{6}

Decimal Notation

x = - 2.74227 \dots, x = 2.74227 \dots

Solution steps

9 x^{2} - 9 ∣ x ∣ - 43 = 0

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

x = - \frac{3 + 181}{6} or x = \frac{3 + 181}{6}

5 ∣ 6 v - 2 ∣ = 5

2 ∣ 2 x + 4 ∣ - 1 = 12 x + 5

4 ∣ x + 6 ∣ = 24

∣ x + 2 ∣ - 4 = 11

0 = ∣ x - 4 ∣ - 4

What is the answer to 9x^2-9|x|-43=0 ?
The answer to 9x^2-9|x|-43=0 is x=-(3+sqrt(181))/6 \lor x=(3+sqrt(181))/6
Solve for x: 9x^2-9|x|-43=0
The solution is x=-(3+sqrt(181))/6 \lor x=(3+sqrt(181))/6