What is the answer to x+|x^2+4-4x|=2 ?

The answer to x+|x^2+4-4x|=2 is x=1\lor x=2

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x+|x^2+4-4x|=2

x + x^{2} + 4 - 4 x = 2

x = 1 or x = 2

Solution steps

x + x^{2} + 4 - 4 x = 2

Find positive and negative intervals

- \infty < x < \infty

Solve the inequality for each interval

(x = 1 or x = 2)

x = 1 or x = 2

∣ 4 k ∣ = 8

\frac{x}{2} + 6 = 10

∣ - 4 f ∣ = 4

∣ 3 x + 4 ∣ = 2 x + 1

∣ 5 x ∣ + 3 = 18

What is the answer to x+|x^2+4-4x|=2 ?
The answer to x+|x^2+4-4x|=2 is x=1\lor x=2
Solve for x: x+|x^2+4-4x|=2
The solution is x=1\lor x=2