What are the solutions to the equation 5x^2+75=40x ?

The solutions to the equation 5x^2+75=40x are x=5,x=3

Find the zeros of 5x^2+75=40x

The zeros of 5x^2+75=40x are x=5,x=3

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5 x^{2} + 75 = 40 x

x = 5, x = 3

Solution steps

5 x^{2} + 75 = 40 x

Move

40 x

to the left side

5 x^{2} + 75 - 40 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 40 x + 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 5 \cdot 75}{2 \cdot 5}

(- 40)^{2} - 4 \cdot 5 \cdot 75 = 10

x_{1, 2} = \frac{- ( - 40 ) \pm 10}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 10}{2 \cdot 5}, x_{2} = \frac{- ( - 40 ) - 10}{2 \cdot 5}

x = \frac{- ( - 40 ) + 10}{2 \cdot 5} : 5

x = \frac{- ( - 40 ) - 10}{2 \cdot 5} : 3

The solutions to the quadratic equation are:

x = 5, x = 3

- 3 \leq 5 x - 7 < 8

\frac{x}{- 6} - 8 \leq - 12

\frac{x - 6}{x - 8} > 0

4 (x - 1) - 2 (3 x + 5) = - 3 x + 1

\frac{- 2 ( x + 1 )}{( 3 )} = 2 - x

What are the solutions to the equation 5x^2+75=40x ?
The solutions to the equation 5x^2+75=40x are x=5,x=3
Find the zeros of 5x^2+75=40x
The zeros of 5x^2+75=40x are x=5,x=3