What is the answer to |t^2-99|=1 ?

The answer to |t^2-99|=1 is t=-10\lor t=-7sqrt(2)\lor t=7sqrt(2)\lor t=10

Solve for t: |t^2-99|=1

The solution is t=-10\lor t=-7sqrt(2)\lor t=7sqrt(2)\lor t=10

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t^{2} - 99 = 1

t = - 10 or t = - 72 or t = 72 or t = 10

Decimal Notation

t = - 10, t = - 9.89949 \dots, t = 9.89949 \dots, t = 10

Solution steps

t^{2} - 99 = 1

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

t^{2} - 99 = - 1 or t^{2} - 99 = 1

t^{2} - 99 = - 1 or t^{2} - 99 = 1

(t = - 72 or t = 72) or (t = - 10 or t = 10)

t = - 10 or t = - 72 or t = 72 or t = 10

- 4 ∣ 4 - 8 b ∣ = 12

- 3 ∣ x + 2 ∣ + 6 = 15

9 = ∣ 2 x - 5 ∣

∣ U - 2 ∣ = - \frac{1}{2}

2 ∣ 3 x - 4 ∣ + 1 = 3

What is the answer to |t^2-99|=1 ?
The answer to |t^2-99|=1 is t=-10\lor t=-7sqrt(2)\lor t=7sqrt(2)\lor t=10
Solve for t: |t^2-99|=1
The solution is t=-10\lor t=-7sqrt(2)\lor t=7sqrt(2)\lor t=10