What is factor n^2-14n+40 ?

The solution to factor n^2-14n+40 is (n-4)(n-10)

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factor n^2-14n+40

factor

n^{2} - 14 n + 40

(n - 4) (n - 10)

Solution steps

n^{2} - 14 n + 40

Break the expression into groups

= (n^{2} - 4 n) + (- 10 n + 40)

Factor out

n

from

n^{2} - 4 n : n (n - 4)

Factor out

- 10

from

- 10 n + 40 : - 10 (n - 4)

= n (n - 4) - 10 (n - 4)

Factor out common term

n - 4

= (n - 4) (n - 10)

\frac{3}{2 - 5}

\frac{x ^{- 3} y ^{0} \cdot ( x y ^{- 3} ) ^{2}}{2 x ^{0}}

4 (x + 6) = 36

x + x + 4 + 2 = 8

p^{2} = \frac{9}{64}