What are the solutions to the equation -2a^2+31a+16=0 ?

The solutions to the equation -2a^2+31a+16=0 are a=-1/2 ,a=16

Find the zeros of -2a^2+31a+16=0

The zeros of -2a^2+31a+16=0 are a=-1/2 ,a=16

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- 2 a^{2} + 31 a + 16 = 0

a = - \frac{1}{2}, a = 16

Decimal Notation

a = - 0.5, a = 16

Solution steps

- 2 a^{2} + 31 a + 16 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 31 \pm 3 1 ^{2} - 4 ( - 2 ) \cdot 16}{2 ( - 2 )}

3 1^{2} - 4 (- 2) \cdot 16 = 33

a_{1, 2} = \frac{- 31 \pm 33}{2 ( - 2 )}

Separate the solutions

a_{1} = \frac{- 31 + 33}{2 ( - 2 )}, a_{2} = \frac{- 31 - 33}{2 ( - 2 )}

a = \frac{- 31 + 33}{2 ( - 2 )} : - \frac{1}{2}

a = \frac{- 31 - 33}{2 ( - 2 )} : 16

The solutions to the quadratic equation are:

a = - \frac{1}{2}, a = 16

- 12 = - 4 x

lo g_{27} (3)

(x - 17)^{2} = 25

d (5) = \frac{5}{16} (2)^{5 - 1}

\frac{x}{2} - 3 = 7

What are the solutions to the equation -2a^2+31a+16=0 ?
The solutions to the equation -2a^2+31a+16=0 are a=-1/2 ,a=16
Find the zeros of -2a^2+31a+16=0
The zeros of -2a^2+31a+16=0 are a=-1/2 ,a=16