What is the answer to |x^2-3x+1|=6+x ?

The answer to |x^2-3x+1|=6+x is x=-1\lor x=5

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|x^2-3x+1|=6+x

x^{2} - 3 x + 1 = 6 + x

x = - 1 or x = 5

Solution steps

x^{2} - 3 x + 1 = 6 + x

Find positive and negative intervals

x \leq \frac{- 5 + 3}{2}, \frac{- 5 + 3}{2} < x < \frac{5 + 3}{2}, x \geq \frac{5 + 3}{2}

Solve the inequality for each interval

x = - 1 or No Solution or x = 5

x = - 1 or x = 5

∣ 3 x + 2 ∣ + 4 x = - 6

x ∣ x ∣ = 1

x ∣ x ∣ = 9

9 ∣ j ∣ = 0

∣ x - 3 ∣ + 3 x = 9

What is the answer to |x^2-3x+1|=6+x ?
The answer to |x^2-3x+1|=6+x is x=-1\lor x=5
Solve for x: |x^2-3x+1|=6+x
The solution is x=-1\lor x=5