What are the solutions to the equation x^2-7x-3=0 ?

The solutions to the equation x^2-7x-3=0 are x=(7+sqrt(61))/2 ,x=(7-sqrt(61))/2

Find the zeros of x^2-7x-3=0

The zeros of x^2-7x-3=0 are x=(7+sqrt(61))/2 ,x=(7-sqrt(61))/2

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x^{2} - 7 x - 3 = 0

x = \frac{7 + 61}{2}, x = \frac{7 - 61}{2}

Decimal Notation

x = 7.40512 \dots, x = - 0.40512 \dots

Solution steps

x^{2} - 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 3) = 61

x_{1, 2} = \frac{- ( - 7 ) \pm 61}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 61}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 61}{2 \cdot 1}

x = \frac{- ( - 7 ) + 61}{2 \cdot 1} : \frac{7 + 61}{2}

x = \frac{- ( - 7 ) - 61}{2 \cdot 1} : \frac{7 - 61}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 61}{2}, x = \frac{7 - 61}{2}

\frac{5}{2} x + \frac{2}{1} x \leq \frac{1}{5} - \frac{1}{1}

x^{10} - y^{6}

7 x^{- 3}

36 a^{2} - 25

\frac{7 !}{( 7 - 5 ) !}

What are the solutions to the equation x^2-7x-3=0 ?
The solutions to the equation x^2-7x-3=0 are x=(7+sqrt(61))/2 ,x=(7-sqrt(61))/2
Find the zeros of x^2-7x-3=0
The zeros of x^2-7x-3=0 are x=(7+sqrt(61))/2 ,x=(7-sqrt(61))/2