What is the answer to |x-1|-x^2+2=0 ?

The answer to |x-1|-x^2+2=0 is x=-(1+sqrt(13))/2 \lor x=(1+sqrt(5))/2

Solve for x: |x-1|-x^2+2=0

The solution is x=-(1+sqrt(13))/2 \lor x=(1+sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

∣ x - 1 ∣ - x^{2} + 2 = 0

x = - \frac{1 + 13}{2} or x = \frac{1 + 5}{2}

Decimal Notation

x = - 2.30277 \dots, x = 1.61803 \dots

Solution steps

∣ x - 1 ∣ - x^{2} + 2 = 0

Find positive and negative intervals

x < 1, x \geq 1

Solve the inequality for each interval

x = - \frac{1 + 13}{2} or x = \frac{1 + 5}{2}

- 3 ∣ 3 t - 4 ∣ - 12 = - 6

∣ 2 x + 7 ∣ = x - 1

3 ∣ x - 5 ∣ = - 2 x - 7

y, ∣ y + 2 ∣ = x

∣ 10 x - 8 ∣ - 3 = 35

What is the answer to |x-1|-x^2+2=0 ?
The answer to |x-1|-x^2+2=0 is x=-(1+sqrt(13))/2 \lor x=(1+sqrt(5))/2
Solve for x: |x-1|-x^2+2=0
The solution is x=-(1+sqrt(13))/2 \lor x=(1+sqrt(5))/2