What is 6/(5x^3y)-1/(2x^2y^3) ?

The solution to 6/(5x^3y)-1/(2x^2y^3) is (12y^2-5x)/(10x^3y^3)

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simplify 6/(5x^3y)-1/(2x^2y^3)

simplify

\frac{6}{5 x ^{3} y} - \frac{1}{2 x ^{2} y ^{3}}

\frac{12 y ^{2} - 5 x}{10 x ^{3} y ^{3}}

Solution steps

\frac{6}{5 x ^{3} y} - \frac{1}{2 x ^{2} y ^{3}}

Least Common Multiplier of

5 x^{3} y, 2 x^{2} y^{3} : 10 x^{3} y^{3}

Adjust Fractions based on the LCM

= \frac{12 y ^{2}}{10 x ^{3} y ^{3}} - \frac{5 x}{10 x ^{3} y ^{3}}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{12 y ^{2} - 5 x}{10 x ^{3} y ^{3}}

7 y + 1.8 = 50.8

(2 w)^{4}

1 = 7 x^{2} + 6 x

5 x^{2} + 21 x - 9 = 0

\frac{4}{x - 2} + \frac{x}{x + 2} \leq \frac{8 x}{x ^{2} - 4}

What is 6/(5x^3y)-1/(2x^2y^3) ?
The solution to 6/(5x^3y)-1/(2x^2y^3) is (12y^2-5x)/(10x^3y^3)