What are the solutions to the equation -x^2-2x+7=0 ?

The solutions to the equation -x^2-2x+7=0 are x=-1-2sqrt(2),x=2sqrt(2)-1

Find the zeros of -x^2-2x+7=0

The zeros of -x^2-2x+7=0 are x=-1-2sqrt(2),x=2sqrt(2)-1

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- x^{2} - 2 x + 7 = 0

x = - 1 - 22, x = 22 - 1

Decimal Notation

x = - 3.82842 \dots, x = 1.82842 \dots

Solution steps

- x^{2} - 2 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 7}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 7 = 42

x_{1, 2} = \frac{- ( - 2 ) \pm 4 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 2}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 4 2}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 4 2}{2 ( - 1 )} : - 1 - 22

x = \frac{- ( - 2 ) - 4 2}{2 ( - 1 )} : 22 - 1

The solutions to the quadratic equation are:

x = - 1 - 22, x = 22 - 1

7 k^{3} + 14 k^{2} + 6 k + 12

α^{2} - 4 α + 13 = 0

(x - 2)^{2} = - 6

(5)^{\frac{7}{3}}

\frac{6 !}{2 ! 4 !}

What are the solutions to the equation -x^2-2x+7=0 ?
The solutions to the equation -x^2-2x+7=0 are x=-1-2sqrt(2),x=2sqrt(2)-1
Find the zeros of -x^2-2x+7=0
The zeros of -x^2-2x+7=0 are x=-1-2sqrt(2),x=2sqrt(2)-1