What are the solutions to the equation 4(x+2)^2=11 ?

The solutions to the equation 4(x+2)^2=11 are x=(sqrt(11))/2-2,x=-(sqrt(11))/2-2

Find the zeros of 4(x+2)^2=11

The zeros of 4(x+2)^2=11 are x=(sqrt(11))/2-2,x=-(sqrt(11))/2-2

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4 (x + 2)^{2} = 11

x = \frac{11}{2} - 2, x = - \frac{11}{2} - 2

Decimal Notation

x = - 0.34168 \dots, x = - 3.65831 \dots

Solution steps

4 (x + 2)^{2} = 11

Divide both sides by

4

(x + 2)^{2} = \frac{11}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = \frac{11}{4} : x = \frac{11}{2} - 2

Solve

x + 2 = - \frac{11}{4} : x = - \frac{11}{2} - 2

The solutions to the quadratic equation are:

x = \frac{11}{2} - 2, x = - \frac{11}{2} - 2

4 - 5 ∣ 2 + 4 x ∣ = - 46

x^{4} - 2 x^{3} + x^{2}

- 7 d - 3 > 2 d - 10

8 a^{3} + 4 a^{2} + 12 a

80 = 100 - 6.25 (x - 9)^{2}

What are the solutions to the equation 4(x+2)^2=11 ?
The solutions to the equation 4(x+2)^2=11 are x=(sqrt(11))/2-2,x=-(sqrt(11))/2-2
Find the zeros of 4(x+2)^2=11
The zeros of 4(x+2)^2=11 are x=(sqrt(11))/2-2,x=-(sqrt(11))/2-2