What are the solutions to the equation (x+6)^2+10(x+6)+21=0 ?

The solutions to the equation (x+6)^2+10(x+6)+21=0 are x=-9,x=-13

Find the zeros of (x+6)^2+10(x+6)+21=0

The zeros of (x+6)^2+10(x+6)+21=0 are x=-9,x=-13

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(x + 6)^{2} + 10 (x + 6) + 21 = 0

x = - 9, x = - 13

Solution steps

(x + 6)^{2} + 10 (x + 6) + 21 = 0

Expand

(x + 6)^{2} + 10 (x + 6) + 21 : x^{2} + 22 x + 117

x^{2} + 22 x + 117 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 1 \cdot 117}{2 \cdot 1}

2 2^{2} - 4 \cdot 1 \cdot 117 = 4

x_{1, 2} = \frac{- 22 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 22 + 4}{2 \cdot 1}, x_{2} = \frac{- 22 - 4}{2 \cdot 1}

x = \frac{- 22 + 4}{2 \cdot 1} : - 9

x = \frac{- 22 - 4}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = - 9, x = - 13

x^{2} - 11 x > - 28

3 x + 2 - 4 x + 1 + 9 x = 6 x - 1

2 n u - 8 u + 3 n - 12

27 - 12

2 y^{2} - 5 y - 3

What are the solutions to the equation (x+6)^2+10(x+6)+21=0 ?
The solutions to the equation (x+6)^2+10(x+6)+21=0 are x=-9,x=-13
Find the zeros of (x+6)^2+10(x+6)+21=0
The zeros of (x+6)^2+10(x+6)+21=0 are x=-9,x=-13