What are the solutions to the equation -7x+1-10x^2=0 ?

The solutions to the equation -7x+1-10x^2=0 are x=-(7+sqrt(89))/(20),x=(sqrt(89)-7)/(20)

Find the zeros of -7x+1-10x^2=0

The zeros of -7x+1-10x^2=0 are x=-(7+sqrt(89))/(20),x=(sqrt(89)-7)/(20)

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- 7 x + 1 - 10 x^{2} = 0

x = - \frac{7 + 89}{20}, x = \frac{89 - 7}{20}

Decimal Notation

x = - 0.82169 \dots, x = 0.12169 \dots

Solution steps

- 7 x + 1 - 10 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 10 x^{2} - 7 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 10 ) \cdot 1}{2 ( - 10 )}

(- 7)^{2} - 4 (- 10) \cdot 1 = 89

x_{1, 2} = \frac{- ( - 7 ) \pm 89}{2 ( - 10 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 89}{2 ( - 10 )}, x_{2} = \frac{- ( - 7 ) - 89}{2 ( - 10 )}

x = \frac{- ( - 7 ) + 89}{2 ( - 10 )} : - \frac{7 + 89}{20}

x = \frac{- ( - 7 ) - 89}{2 ( - 10 )} : \frac{89 - 7}{20}

The solutions to the quadratic equation are:

x = - \frac{7 + 89}{20}, x = \frac{89 - 7}{20}

250 x^{3} + 128

z^{2} + 7 z + 12

\frac{x + 15}{- 3} > - 7

72 a^{8} b^{5}

\frac{- 8 x ^{2} - 48 x y - 72 y ^{2}}{2 x ^{2} - 18 y ^{2}}

What are the solutions to the equation -7x+1-10x^2=0 ?
The solutions to the equation -7x+1-10x^2=0 are x=-(7+sqrt(89))/(20),x=(sqrt(89)-7)/(20)
Find the zeros of -7x+1-10x^2=0
The zeros of -7x+1-10x^2=0 are x=-(7+sqrt(89))/(20),x=(sqrt(89)-7)/(20)