What is the answer to |4x^2+8x+3|=1 ?

The answer to |4x^2+8x+3|=1 is x=-(sqrt(2)+1}{sqrt(2)}\lor x=-1\lor x=\frac{-2+sqrt(2))/2

Solve for x: |4x^2+8x+3|=1

The solution is x=-(sqrt(2)+1}{sqrt(2)}\lor x=-1\lor x=\frac{-2+sqrt(2))/2

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4 x^{2} + 8 x + 3 = 1

x = - \frac{2 + 1}{2} or x = - 1 or x = \frac{- 2 + 2}{2}

Decimal Notation

x = - 1.70710 \dots, x = - 1, x = - 0.29289 \dots

Solution steps

4 x^{2} + 8 x + 3 = 1

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

4 x^{2} + 8 x + 3 = - 1 or 4 x^{2} + 8 x + 3 = 1

4 x^{2} + 8 x + 3 = - 1 or 4 x^{2} + 8 x + 3 = 1

x = - 1 or (x = - \frac{2 + 1}{2} or x = \frac{- 2 + 2}{2})

x = - \frac{2 + 1}{2} or x = - 1 or x = \frac{- 2 + 2}{2}

∣ d ∣ + 9 = 11

∣ x + 7 ∣ + 9 = 8

∣ x + 7 ∣ + 9 = 5

∣ x - 3 ∣ - 1 = 0

∣ a + 5 ∣ = a + 5

What is the answer to |4x^2+8x+3|=1 ?
The answer to |4x^2+8x+3|=1 is x=-(sqrt(2)+1}{sqrt(2)}\lor x=-1\lor x=\frac{-2+sqrt(2))/2
Solve for x: |4x^2+8x+3|=1
The solution is x=-(sqrt(2)+1}{sqrt(2)}\lor x=-1\lor x=\frac{-2+sqrt(2))/2