What are the solutions to the equation -64t^2=1 ?

The solutions to the equation -64t^2=1 are t= 1/8 i,t=-1/8 i

Find the zeros of -64t^2=1

The zeros of -64t^2=1 are t= 1/8 i,t=-1/8 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 64 t^{2} = 1

t = \frac{1}{8} i, t = - \frac{1}{8} i

Solution steps

- 64 t^{2} = 1

Divide both sides by

- 64

t^{2} = - \frac{1}{64}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = - \frac{1}{64}, t = - - \frac{1}{64}

- \frac{1}{64} = \frac{1}{8} i

- - \frac{1}{64} = - \frac{1}{8} i

t = \frac{1}{8} i, t = - \frac{1}{8} i

3 x^{5} y^{2} - 12 x^{3} y^{5}

10 - 4 x \leq - 6

lo g_{2} (\frac{1}{6})

- 1 \cdot \frac{1}{2}

\frac{1}{5} + \frac{2}{3}

What are the solutions to the equation -64t^2=1 ?
The solutions to the equation -64t^2=1 are t= 1/8 i,t=-1/8 i
Find the zeros of -64t^2=1
The zeros of -64t^2=1 are t= 1/8 i,t=-1/8 i