What is the answer to |x^2-4x|=2x+1 ?

The answer to |x^2-4x|=2x+1 is x=3-sqrt(10)\lor x=1\lor x=3+sqrt(10)

Solve for x: |x^2-4x|=2x+1

The solution is x=3-sqrt(10)\lor x=1\lor x=3+sqrt(10)

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x^{2} - 4 x = 2 x + 1

x = 3 - 10 or x = 1 or x = 3 + 10

Decimal Notation

x = - 0.16227 \dots, x = 1, x = 6.16227 \dots

Solution steps

x^{2} - 4 x = 2 x + 1

Find positive and negative intervals

x \leq 0, 0 < x < 4, x \geq 4

Solve the inequality for each interval

x = 3 - 10 or x = 1 or x = 3 + 10

∣ 8 y - 8 ∣ = 8

- 5 ∣ 5 m - 5 ∣ = - 73

- ∣ 3 + x ∣ = 5

∣ m + 1 ∣ = 3

∣ m + 1 ∣ = 6

What is the answer to |x^2-4x|=2x+1 ?
The answer to |x^2-4x|=2x+1 is x=3-sqrt(10)\lor x=1\lor x=3+sqrt(10)
Solve for x: |x^2-4x|=2x+1
The solution is x=3-sqrt(10)\lor x=1\lor x=3+sqrt(10)