What is (18x^3y^3z^2)/(45xy^4z^4) ?

The solution to (18x^3y^3z^2)/(45xy^4z^4) is (2x^2)/(5yz^2)

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simplify (18x^3y^3z^2)/(45xy^4z^4)

simplify

\frac{18 x ^{3} y ^{3} z ^{2}}{45 x y ^{4} z ^{4}}

\frac{2 x ^{2}}{5 y z ^{2}}

Solution steps

\frac{18 x ^{3} y ^{3} z ^{2}}{45 x y ^{4} z ^{4}}

Factor the number:

18 = 9 \cdot 2

= \frac{9 \cdot 2 x ^{3} y ^{3} z ^{2}}{45 x y ^{4} z ^{4}}

Factor the number:

45 = 9 \cdot 5

= \frac{9 \cdot 2 x ^{3} y ^{3} z ^{2}}{9 \cdot 5 x y ^{4} z ^{4}}

Cancel the common factor:

9

= \frac{2 x ^{3} y ^{3} z ^{2}}{5 x y ^{4} z ^{4}}

Simplify

\frac{x ^{3}}{x} : x^{2}

= \frac{2 x ^{2} y ^{3} z ^{2}}{5 y ^{4} z ^{4}}

Simplify

\frac{y ^{3}}{y ^{4}} : \frac{1}{y}

= \frac{2 x ^{2} z ^{2}}{5 y z ^{4}}

Simplify

\frac{z ^{2}}{z ^{4}} : \frac{1}{z ^{2}}

= \frac{2 x ^{2}}{5 y z ^{2}}

\frac{2}{3} s - \frac{5}{6} s + \frac{1}{2} = - \frac{3}{2}

2 x = 16

\frac{14 x ^{6} y ^{4}}{7 x ^{5} y ^{3}}

4 x^{2} = - 6 x - 1

6 - Q = - 2 + Q

What is (18x^3y^3z^2)/(45xy^4z^4) ?
The solution to (18x^3y^3z^2)/(45xy^4z^4) is (2x^2)/(5yz^2)