What is the answer to |(3x-5)(x+2)|=4 ?

The answer to |(3x-5)(x+2)|=4 is x=-7/3 \lor x=(-1-sqrt(73))/6 \lor x=(-1+sqrt(73))/6 \lor x=2

Solve for x: |(3x-5)(x+2)|=4

The solution is x=-7/3 \lor x=(-1-sqrt(73))/6 \lor x=(-1+sqrt(73))/6 \lor x=2

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∣ (3 x - 5) (x + 2) ∣ = 4

x = - \frac{7}{3} or x = \frac{- 1 - 73}{6} or x = \frac{- 1 + 73}{6} or x = 2

Decimal Notation

x = - 2.33333 \dots, x = - 1.59066 \dots, x = 1.25733 \dots, x = 2

Solution steps

∣ (3 x - 5) (x + 2) ∣ = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

(3 x - 5) (x + 2) = - 4 or (3 x - 5) (x + 2) = 4

(3 x - 5) (x + 2) = - 4 or (3 x - 5) (x + 2) = 4

(x = \frac{- 1 - 73}{6} or x = \frac{- 1 + 73}{6}) or (x = - \frac{7}{3} or x = 2)

x = - \frac{7}{3} or x = \frac{- 1 - 73}{6} or x = \frac{- 1 + 73}{6} or x = 2

0 = ∣ z - 5 ∣

- 4 ∣ 9 + x ∣ = - 40

0 = 3 - ∣ x + 4 ∣

ln (ln (y)) = - ln ∣ x ∣

∣ - 5 n ∣ - 3 = 12

What is the answer to |(3x-5)(x+2)|=4 ?
The answer to |(3x-5)(x+2)|=4 is x=-7/3 \lor x=(-1-sqrt(73))/6 \lor x=(-1+sqrt(73))/6 \lor x=2
Solve for x: |(3x-5)(x+2)|=4
The solution is x=-7/3 \lor x=(-1-sqrt(73))/6 \lor x=(-1+sqrt(73))/6 \lor x=2