What is the answer to log_{5}(6-5^x)=1-x ?

The answer to log_{5}(6-5^x)=1-x is x=0,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{5}(6-5^x)=1-x

lo g_{5} (6 - 5^{x}) = 1 - x

x = 0, x = 1

Solution steps

lo g_{5} (6 - 5^{x}) = 1 - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

5^{l o g_{5} (6 - 5^{x})} = 5^{1 - x}

Simplify

5^{l o g_{5} (6 - 5^{x})} : 6 - 5^{x}

6 - 5^{x} = 5^{1 - x}

Solve

6 - 5^{x} = 5^{1 - x} : x = 0, x = 1

x = 0, x = 1

Verify Solutions:

x = 0

True

, x = 1

True

The solutions are

x = 0, x = 1

lo g_{3} (x) = 3

ln (x^{2} + x) + ln (e) = ln (x + 1)

lo g_{x} (81) = 4

ln (3 x - 10) = 2

lo g_{4} (x) = 2

What is the answer to log_{5}(6-5^x)=1-x ?
The answer to log_{5}(6-5^x)=1-x is x=0,x=1
Solve for x: log_{5}(6-5^x)=1-x
The solution is x=0,x=1