What is the answer to solvefor x,ln(x)+ln(x-1)=1 ?

The answer to solvefor x,ln(x)+ln(x-1)=1 is x=(1+sqrt(1+4e))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,ln(x)+ln(x-1)=1

solve for

x, ln (x) + ln (x - 1) = 1

x = \frac{1 + 1 + 4 e}{2}

Decimal

x = 2.22287 \dots

Solution steps

ln (x) + ln (x - 1) = 1

Apply log rules

x (x - 1) = e

Solve

x (x - 1) = e : x = \frac{1 + 1 + 4 e}{2}, x = \frac{1 - 1 + 4 e}{2}

x = \frac{1 + 1 + 4 e}{2}, x = \frac{1 - 1 + 4 e}{2}

Verify Solutions:

x = \frac{1 + 1 + 4 e}{2}

True

, x = \frac{1 - 1 + 4 e}{2}

False

The solution is

x = \frac{1 + 1 + 4 e}{2}

lo g_{16} (a) = lo g_{2} (x)

lo g_{x} (25) = 2

lo g_{32} (a) = lo g_{2} (x)

lo g_{x} (125) = 3

lo g_{243} (a) = lo g_{3} (x)

What is the answer to solvefor x,ln(x)+ln(x-1)=1 ?
The answer to solvefor x,ln(x)+ln(x-1)=1 is x=(1+sqrt(1+4e))/2