What is the answer to ln(x^2)+log_{7}(x)=2 ?

The answer to ln(x^2)+log_{7}(x)=2 is x=7^{(2log_{7}(e))/(2+log_{7)(e)}}

Solve for x: ln(x^2)+log_{7}(x)=2

The solution is x=7^{(2log_{7}(e))/(2+log_{7)(e)}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln (x^{2}) + lo g_{7} (x) = 2

x = 7^{\frac{2 l o g _{7} ( e )}{2 + l o g _{7} ( e )}}

Decimal Notation

x = 2.21571 \dots

Solution steps

ln (x^{2}) + lo g_{7} (x) = 2

Apply log rules

x = 7^{\frac{2 l o g _{7} ( e )}{2 + l o g _{7} ( e )}}

Verify Solutions:

x = 7^{\frac{2 l o g _{7} ( e )}{2 + l o g _{7} ( e )}}

True

The solution is

x = 7^{\frac{2 l o g _{7} ( e )}{2 + l o g _{7} ( e )}}

2 = - lo g_{10} (x)

lo g_{x} (343) = 3

lo g_{8} (a) = lo g_{2} (x)

3 ln (x^{4}) = 18

lo g_{9} (a) = lo g_{3} (x)

What is the answer to ln(x^2)+log_{7}(x)=2 ?
The answer to ln(x^2)+log_{7}(x)=2 is x=7^{(2log_{7}(e))/(2+log_{7)(e)}}
Solve for x: ln(x^2)+log_{7}(x)=2
The solution is x=7^{(2log_{7}(e))/(2+log_{7)(e)}}