What is the answer to log_{2}(m-6)+log_{2}(m+1)=3 ?

The answer to log_{2}(m-6)+log_{2}(m+1)=3 is m=7

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log_{2}(m-6)+log_{2}(m+1)=3

lo g_{2} (m - 6) + lo g_{2} (m + 1) = 3

m = 7

Solution steps

lo g_{2} (m - 6) + lo g_{2} (m + 1) = 3

Apply log rules

(m - 6) (m + 1) = 8

Solve

(m - 6) (m + 1) = 8 : m = 7, m = - 2

m = 7, m = - 2

Verify Solutions:

m = 7

True

, m = - 2

False

The solution is

m = 7

lo g_{4}^{2} (1 + x^{2}) = 0.25

lo g_{10} (\frac{x}{3}) = 2

lo g_{x} (16) = 4

ln (ln (x)) = 0

lo g_{4} (a) = lo g_{2} (x)

What is the answer to log_{2}(m-6)+log_{2}(m+1)=3 ?
The answer to log_{2}(m-6)+log_{2}(m+1)=3 is m=7
Solve for m: log_{2}(m-6)+log_{2}(m+1)=3
The solution is m=7