What is the answer to log_{2}(x+1)+log_{2}(x-1)=3 ?

The answer to log_{2}(x+1)+log_{2}(x-1)=3 is x=3

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log_{2}(x+1)+log_{2}(x-1)=3

lo g_{2} (x + 1) + lo g_{2} (x - 1) = 3

x = 3

Solution steps

lo g_{2} (x + 1) + lo g_{2} (x - 1) = 3

Apply log rules

(x + 1) (x - 1) = 8

Solve

(x + 1) (x - 1) = 8 : x = 3, x = - 3

x = 3, x = - 3

Verify Solutions:

x = 3

True

, x = - 3

False

The solution is

x = 3

lo g_{x} (32) = 5

lo g_{3} (x) + lo g_{3} (x - 6) = 3

ln (x) = x

lo g_{10} (x - 3) + lo g_{10} (5) = 2

lo g_{x} (4) = - \frac{1}{2}

What is the answer to log_{2}(x+1)+log_{2}(x-1)=3 ?
The answer to log_{2}(x+1)+log_{2}(x-1)=3 is x=3
Solve for x: log_{2}(x+1)+log_{2}(x-1)=3
The solution is x=3