What is the answer to log_{10}(2x^2-5)=0 ?

The answer to log_{10}(2x^2-5)=0 is x=sqrt(3),x=-sqrt(3)

Solve for x: log_{10}(2x^2-5)=0

The solution is x=sqrt(3),x=-sqrt(3)

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lo g_{10} (2 x^{2} - 5) = 0

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

lo g_{10} (2 x^{2} - 5) = 0

Apply log rules

2 x^{2} - 5 = 1

Solve

2 x^{2} - 5 = 1 : x = 3, x = - 3

x = 3, x = - 3

lo g_{x} (8) = 3

lo g_{5} (3 x - 8) = 2

lo g_{x} (16) = 2

ln (x) + ln (2) = ln (5)

lo g_{4} (3 x + 2) - lo g_{4} (x - 3) = 1

What is the answer to log_{10}(2x^2-5)=0 ?
The answer to log_{10}(2x^2-5)=0 is x=sqrt(3),x=-sqrt(3)
Solve for x: log_{10}(2x^2-5)=0
The solution is x=sqrt(3),x=-sqrt(3)