What is the answer to ln(x)+ln(x-3)=0 ?

The answer to ln(x)+ln(x-3)=0 is x=(3+sqrt(13))/2

Solve for x: ln(x)+ln(x-3)=0

The solution is x=(3+sqrt(13))/2

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ln (x) + ln (x - 3) = 0

x = \frac{3 + 13}{2}

Decimal Notation

x = 3.30277 \dots

Solution steps

ln (x) + ln (x - 3) = 0

Apply log rules

x (x - 3) = 1

Solve

x (x - 3) = 1 : x = \frac{3 + 13}{2}, x = \frac{3 - 13}{2}

x = \frac{3 + 13}{2}, x = \frac{3 - 13}{2}

Verify Solutions:

x = \frac{3 + 13}{2}

True

, x = \frac{3 - 13}{2}

False

The solution is

x = \frac{3 + 13}{2}

ln (x + 5) = ln (x - 1) - ln (x + 1)

x, ln (y) = ln (x)

2 lo g_{3} (x) = lo g_{x} (9)

lo g_{10} (x - 1) = 2

ln (x) + ln (x - 1) = 0

What is the answer to ln(x)+ln(x-3)=0 ?
The answer to ln(x)+ln(x-3)=0 is x=(3+sqrt(13))/2
Solve for x: ln(x)+ln(x-3)=0
The solution is x=(3+sqrt(13))/2