What is the answer to log_{10}(3)+log_{10}(1-3x)=0 ?

The answer to log_{10}(3)+log_{10}(1-3x)=0 is x= 2/9

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log_{10}(3)+log_{10}(1-3x)=0

lo g_{10} (3) + lo g_{10} (1 - 3 x) = 0

x = \frac{2}{9}

Decimal Notation

x = 0.22222 \dots

Solution steps

lo g_{10} (3) + lo g_{10} (1 - 3 x) = 0

Move

lo g_{10} (3)

to the right side

lo g_{10} (1 - 3 x) = - lo g_{10} (3)

Apply log rules

1 - 3 x = \frac{1}{3}

Solve

1 - 3 x = \frac{1}{3} : x = \frac{2}{9}

x = \frac{2}{9}

Verify Solutions:

x = \frac{2}{9}

True

The solution is

x = \frac{2}{9}

lo g_{6} (x) = 3

lo g_{3} (x) = 1

- lo g_{10} (x) = 2.3

ln (x) = 7

lo g_{x} (64) = 2

What is the answer to log_{10}(3)+log_{10}(1-3x)=0 ?
The answer to log_{10}(3)+log_{10}(1-3x)=0 is x= 2/9
Solve for x: log_{10}(3)+log_{10}(1-3x)=0
The solution is x= 2/9