What is the answer to ln(x)-ln(x^2)=5 ?

The answer to ln(x)-ln(x^2)=5 is x= 1/(e^5)

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ln(x)-ln(x^2)=5

ln (x) - ln (x^{2}) = 5

x = \frac{1}{e ^{5}}

Decimal Notation

x = 0.00673 \dots

Solution steps

ln (x) - ln (x^{2}) = 5

Apply log rules

x = \frac{1}{e ^{5}}

Verify Solutions:

x = \frac{1}{e ^{5}}

True

The solution is

x = \frac{1}{e ^{5}}

lo g_{10} (x^{3} + 2000) = 2

lo g_{x} (49) = 2

lo g_{2} (x + 7) + lo g_{2} (x) = 3

lo g_{3} (x + 3) + lo g_{3} (x + 5) = 1

1 - ln (x) = 0

What is the answer to ln(x)-ln(x^2)=5 ?
The answer to ln(x)-ln(x^2)=5 is x= 1/(e^5)
Solve for x: ln(x)-ln(x^2)=5
The solution is x= 1/(e^5)